Results for: "uri"

“foo #{bar}” ^^^^^^^^^^^^

‘foo #{bar}` ^^^^^^^^^^^^

/(?<foo>foo)/ =~ bar ^^^^^^^^^^^^^^^^^^^^

foo, bar = baz ^^^^^^^^^^^^^^

Visit a destructured positional parameter node.

foo = 1 and bar => ^foo

^^^^

__ENCODING__ ^^^^^^^^^^^^

__FILE__ ^^^^^^^^

__LINE__ ^^^^^^^^

Visit a heredoc node that is representing a string.

Visit a heredoc node that is representing an xstring.

Interpolate substitution vars in the arg (i.e. $(DEFFILE))

Example:

x.foo
 ^^^^
x.foo(42)
 ^^^^
x&.foo
 ^^^^^
x[42]
 ^^^^
x.foo = 1
 ^^^^^^
x[42] = 1
 ^^^^^^
x + 1
  ^
+x
^
foo(42)
^^^
foo 42
^^^
foo
^^^

Example:

x.foo(42)
      ^^
x[42]
  ^^
x.foo = 1
        ^
x[42] = 1
  ^^^^^^^
x[] = 1
  ^^^^^
x + 1
    ^
foo(42)
    ^^
foo 42
    ^^

Foo &&= bar

becomes

Foo && Foo = bar

Foo ||= bar

becomes

defined?(Foo) ? Foo : Foo = bar

Foo += bar

becomes

Foo = Foo + bar

Reset nil attributes to their default values to make the spec valid

When there is an invalid block with a keyword missing an end right before another end, it is unclear where which keyword is missing the end

Take this example:

class Dog       # 1
  def bark      # 2
    puts "woof" # 3
end             # 4

However due to github.com/ruby/syntax_suggest/issues/32 the problem line will be identified as:

> class Dog       # 1

Because lines 2, 3, and 4 are technically valid code and are expanded first, deemed valid, and hidden. We need to un-hide the matching end line 4. Also work backwards and if there’s a mis-matched keyword, show it too

foo => bar => baz

^^^^^^^^^^

Foo = 1 ^^^^^^^

Foo, Bar = 1 ^^^ ^^^