Results for: "Array"

Returns a simpler approximation of the value if the optional argument eps is given (rat-|eps| <= result <= rat+|eps|), self otherwise.

r = Rational(5033165, 16777216)
r.rationalize                    #=> (5033165/16777216)
r.rationalize(Rational('0.01'))  #=> (3/10)
r.rationalize(Rational('0.1'))   #=> (1/3)

Parse an HTTP query string into a hash of key=>value pairs.

params = CGI.parse("query_string")
  # {"name1" => ["value1", "value2", ...],
  #  "name2" => ["value1", "value2", ...], ... }

Creates a date object denoting the present day.

Date.today   #=> #<Date: 2011-06-11 ...>

Parses the given representation of date and time, and returns a hash of parsed elements.

This method **does not** function as a validator. If the input string does not match valid formats strictly, you may get a cryptic result. Should consider to use ‘Date._strptime` or `DateTime._strptime` instead of this method as possible.

If the optional second argument is true and the detected year is in the range “00” to “99”, considers the year a 2-digit form and makes it full.

Date._parse('2001-02-03') #=> {:year=>2001, :mon=>2, :mday=>3}

Raise an ArgumentError when the string length is longer than limit. You can stop this check by passing ‘limit: nil`, but note that it may take a long time to parse.

Parses the given representation of date and time, and creates a date object.

This method **does not** function as a validator. If the input string does not match valid formats strictly, you may get a cryptic result. Should consider to use ‘Date.strptime` instead of this method as possible.

If the optional second argument is true and the detected year is in the range “00” to “99”, considers the year a 2-digit form and makes it full.

Date.parse('2001-02-03')          #=> #<Date: 2001-02-03 ...>
Date.parse('20010203')            #=> #<Date: 2001-02-03 ...>
Date.parse('3rd Feb 2001')        #=> #<Date: 2001-02-03 ...>

Raise an ArgumentError when the string length is longer than limit. You can stop this check by passing ‘limit: nil`, but note that it may take a long time to parse.

Returns the year.

Date.new(2001,2,3).year           #=> 2001
(Date.new(1,1,1) - 1).year        #=> 0

Returns the day of the year (1-366).

Date.new(2001,2,3).yday           #=> 34

Returns the day of the month (1-31).

Date.new(2001,2,3).mday           #=> 3

Returns the day of the month (1-31).

Date.new(2001,2,3).mday           #=> 3

Returns the calendar week based year.

Date.new(2001,2,3).cwyear         #=> 2001
Date.new(2000,1,1).cwyear         #=> 1999

Returns the day of calendar week (1-7, Monday is 1).

Date.new(2001,2,3).cwday          #=> 6

Returns the day of week (0-6, Sunday is zero).

Date.new(2001,2,3).wday           #=> 6

Returns true if the date is Sunday.

Returns true if the date is Monday.

Returns true if the date is Tuesday.

Returns true if the date is Wednesday.

Returns true if the date is Thursday.

Returns true if the date is Friday.

Returns true if the date is Saturday.

Returns the Julian day number denoting the day of calendar reform.

Date.new(2001,2,3).start                  #=> 2299161.0
Date.new(2001,2,3,Date::GREGORIAN).start  #=> -Infinity

Parses the given representation of date and time, and creates a DateTime object.

This method **does not** function as a validator. If the input string does not match valid formats strictly, you may get a cryptic result. Should consider to use ‘DateTime.strptime` instead of this method as possible.

If the optional second argument is true and the detected year is in the range “00” to “99”, makes it full.

DateTime.parse('2001-02-03T04:05:06+07:00')
                          #=> #<DateTime: 2001-02-03T04:05:06+07:00 ...>
DateTime.parse('20010203T040506+0700')
                          #=> #<DateTime: 2001-02-03T04:05:06+07:00 ...>
DateTime.parse('3rd Feb 2001 04:05:06 PM')
                          #=> #<DateTime: 2001-02-03T16:05:06+00:00 ...>

Raise an ArgumentError when the string length is longer than limit. You can stop this check by passing ‘limit: nil`, but note that it may take a long time to parse.

Takes a string representation of a Time and attempts to parse it using a heuristic.

This method **does not** function as a validator. If the input string does not match valid formats strictly, you may get a cryptic result. Should consider to use ‘Time.strptime` instead of this method as possible.

require 'time'

Time.parse("2010-10-31") #=> 2010-10-31 00:00:00 -0500

Any missing pieces of the date are inferred based on the current date.

require 'time'

# assuming the current date is "2011-10-31"
Time.parse("12:00") #=> 2011-10-31 12:00:00 -0500

We can change the date used to infer our missing elements by passing a second object that responds to mon, day and year, such as Date, Time or DateTime. We can also use our own object.

require 'time'

class MyDate
  attr_reader :mon, :day, :year

  def initialize(mon, day, year)
    @mon, @day, @year = mon, day, year
  end
end

d  = Date.parse("2010-10-28")
t  = Time.parse("2010-10-29")
dt = DateTime.parse("2010-10-30")
md = MyDate.new(10,31,2010)

Time.parse("12:00", d)  #=> 2010-10-28 12:00:00 -0500
Time.parse("12:00", t)  #=> 2010-10-29 12:00:00 -0500
Time.parse("12:00", dt) #=> 2010-10-30 12:00:00 -0500
Time.parse("12:00", md) #=> 2010-10-31 12:00:00 -0500

If a block is given, the year described in date is converted by the block. This is specifically designed for handling two digit years. For example, if you wanted to treat all two digit years prior to 70 as the year 2000+ you could write this:

require 'time'

Time.parse("01-10-31") {|year| year + (year < 70 ? 2000 : 1900)}
#=> 2001-10-31 00:00:00 -0500
Time.parse("70-10-31") {|year| year + (year < 70 ? 2000 : 1900)}
#=> 1970-10-31 00:00:00 -0500

If the upper components of the given time are broken or missing, they are supplied with those of now. For the lower components, the minimum values (1 or 0) are assumed if broken or missing. For example:

require 'time'

# Suppose it is "Thu Nov 29 14:33:20 2001" now and
# your time zone is EST which is GMT-5.
now = Time.parse("Thu Nov 29 14:33:20 2001")
Time.parse("16:30", now)     #=> 2001-11-29 16:30:00 -0500
Time.parse("7/23", now)      #=> 2001-07-23 00:00:00 -0500
Time.parse("Aug 31", now)    #=> 2001-08-31 00:00:00 -0500
Time.parse("Aug 2000", now)  #=> 2000-08-01 00:00:00 -0500

Since there are numerous conflicts among locally defined time zone abbreviations all over the world, this method is not intended to understand all of them. For example, the abbreviation “CST” is used variously as:

-06:00 in America/Chicago,
-05:00 in America/Havana,
+08:00 in Asia/Harbin,
+09:30 in Australia/Darwin,
+10:30 in Australia/Adelaide,
etc.

Based on this fact, this method only understands the time zone abbreviations described in RFC 822 and the system time zone, in the order named. (i.e. a definition in RFC 822 overrides the system time zone definition.) The system time zone is taken from Time.local(year, 1, 1).zone and Time.local(year, 7, 1).zone. If the extracted time zone abbreviation does not match any of them, it is ignored and the given time is regarded as a local time.

ArgumentError is raised if Date._parse cannot extract information from date or if the Time class cannot represent specified date.

This method can be used as a fail-safe for other parsing methods as:

Time.rfc2822(date) rescue Time.parse(date)
Time.httpdate(date) rescue Time.parse(date)
Time.xmlschema(date) rescue Time.parse(date)

A failure of Time.parse should be checked, though.

You must require ‘time’ to use this method.

Returns the day of the month (1..31) for time.

t = Time.now   #=> 2007-11-19 08:27:03 -0600
t.day          #=> 19
t.mday         #=> 19

Returns the day of the month (1..31) for time.

t = Time.now   #=> 2007-11-19 08:27:03 -0600
t.day          #=> 19
t.mday         #=> 19

Returns the year for time (including the century).

t = Time.now   #=> 2007-11-19 08:27:51 -0600
t.year         #=> 2007